Answer:
size at this scale of the solar system is 10⁸ m²
Step-by-step explanation:
For this exercise we can use a direct proportions rule or rule of three.
If the radius of the Sun is 7 10⁸ m is equal to the radius of a grapefruit is on average about 5 cm, the radius of the orbit of the plant is x
Mercury
r1 = 5.8 10¹⁰m
x = r1 / r_Sum 5
x = 5.8 10¹⁰/7 10⁸
x = 82 m
We repeat the same formula with all the radii of the orbit, the results in the table
Numb name r_orbit (m) x (m) A (m2)
0 Sun 7 10⁸ 1 3.14
1 mercury 5.8 10¹⁰ 8.2 10¹ 2.0 10⁴
2 venus 1 10¹¹ 1.4 10² 6.2 10⁴
3 Earth 1.5 10¹¹ 2.1 10² 1.4 10⁵
4 Mars 2.3 10¹¹ 3.2 10² 3.2 10⁵
5 Jupiter 7.8 10¹¹ 1.1 10³ 3.8 10⁶
6 Saturn 1.4 10¹² 2 10³ 1.3 10⁷
7 Uranus 2.9 10¹² 4.1 10³ 5.3 10⁷
8 Neptune 4.5 10¹² 6.4 10³ 1.3 10⁸
9 Pluto 5.9 10¹² 8.4 10³ 2.2 10⁸
The area of a circle is
A = π R²
Mercury
A = π 80²
A = 2.0 14 m²
The other values are in the table
The size at this scale of the solar system is 10⁸ m²