Question

17. The length of a rectangle is 12 in, and the perimeter is 56 in. Find the width of the rectangle.

Oo oo
O A. 16 in.
O B. 32 in.
O c. 22 in.
O D. 21 in.

Answer 1

Explanation:

P = 2(L + W)

P = 56

L = 12

now sub...we are looking for w

56 = 2(12 + W)

56 = 24 + 2W

56 - 24 = 2W

32 = 2W

32/2 = W

16 = W <==== the width is 16 inches

check...

P = 2(L + W)

56 = 2(12 + 16)

56 = 2(28)

56 = 56 (correct)