Question

Write the molecular and net ionic equations for the reaction in aqueous solution of sulfuric acid with excess lithium hydroxide.

Answer 1

`H_2SO_4_((aq))+2LiOH_((aq))\rightarrow H_2O_((l))+Li_2SO_4_((aq))`

`2H^+_((aq))+2OH^(-)\rightarrow H_2O_((l))`

Step-by-step explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Only the species which are present in aqueous state dissociate.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a)

The balanced molecular equation will be,

`H_2SO_4_((aq))+2LiOH_((aq))\rightarrow H_2O_((l))+Li_2SO_4_((aq))`

The complete ionic equation in separated aqueous solution will be,

`2H^+_((aq))+SO_4^-_((aq))+2Li^+_((aq))+2OH^(-)_((aq))\rightarrow H_2O_((l))+2Li^+_((aq))+SO_4^-_((aq))`

In this equation the species present are,
`Li^+\text{ and }SO_4^-` are the spectator ions.

Hence, the net ionic equation contains specie is

`2H^+_((aq))+2OH^(-)\rightarrow H_2O_((l))`