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Solve the triangle. B = 73°, b = 15, c = 10

User Nicero
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1 Answer

2 votes

Incomplete Question, the complete question is

Solve the triangle.

B = 73°, b = 15, c = 10

A. C = 39.6°, A = 67.4°, a ≈ 14.5

B. Cannot be solved

C. C = 44.8°, A = 62.4°, a ≈ 14.5

D. C = 39.6°, A = 67.4°, a ≈ 20.3

Answer:

The Answer is the option A

A. C = 39.6°, A = 67.4°, a ≈ 14.5

Explanation:

Given:

In Δ ABC,

∠B = 73°

b = 15

c = 10

To Find:

∠A = ?

∠B = ?

a = ?

Solution:

IN Δ ABC, Sine Rule says that


(a)/(\sin A)= (b)/(\sin B)= (c)/(\sin C)

Substituting the given values we get


(15)/(\sin 73)= (10)/(\sin C)\\\\\sin C=0.6375\\\therefore C=39.6\°

Triangle sum property:

In a Triangle sum of the measures of all the angles of a triangle is 180°.


\angle A+\angle B+\angle C=180\\\\73+39.6+\angle A=180\\\therefore m\angle A =180-112.6=67.4\°


(a)/(\sin A)= (b)/(\sin B)

Substituting the given values we get


(a)/(\sin 67.4)= (15)/(\sin 73)\\\\\therefore a=14.48\approx14.5

Therefore,

A. ∠C = 39.6°, ∠A = 67.4°, a ≈ 14.5

User Bengel
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4.4k points