Answer:
1)
![9(1)/(6)-8(5)/(6)=(1)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vvkmzbsnpi92gfbj51qzsrmuijajg7m55m.png)
2)
![10(3)/(4)-6(4)/(4)=3(3)/(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/h8d1fdkyiwubg8j5v2a3ix94waaxwmdmj9.png)
Explanation:
You can convert he mixed numbers to improper fractions:
1. Multiply the whole number part by the denominator of the fraction.
2. Add the product obtained to the numerator.
3. The denominator does not change.
Then:
![9(1)/(6)=(54+1)/(6)=(55)/(6)\\\\8(5)/(6)=(48+5)/(6)=(53)/(6)\\\\10(3)/(4)=(40+3)/(4)=(43)/(4)\\\\6(4)/(4)=(24+4)/(4)=(28)/(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/i9ltpbvov9m4zp7wis8fwuis39bdw2xjzm.png)
Observe that, in each subtraction, the denominators are equal, then you can rewrite the denominator and subtract the numerators:
![1)\ (55)/(6)-(53)/(6)=(55-53)/(6)= (2)/(6)=(1)/(3) \\\\2)\ (43)/(4)-(28)/(4)=(43-28)/(4)= (15)/(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z7f77hmd3ft1zdw1fuj3vujdxnhlrej7xs.png)
Divide 15 by 4. The quotient will be 3 and the remainder 3.
Then:
![(15)/(4)=3(3)/(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/22oexq83qtkq85kza68b4jzgdlykb8bbzl.png)