Question

PLZ help super fast thanks

Answer 1

B.
`(1)/(x^2y^7)`

Explanation:

Given:

`(x^3y^(-2)z)(x^(-5)y^(-5)z^(-1))`

Hence Solving the given expression we get;

By Law of Indices which states;

`(a^xb^yc^z)(a^pb^qc^r) = a^(x+p)b^(y+q)c^(z+r)`

Hence we get;

`x^(3+(-5))y^((-2)+(-5))z^(1+(-1))\\\\x^(3-5)y^(-2-5)z^(1-1)\\\\x^(-2)y^(-7)`

Also We know that

`a^(-6) =(1)/(a^6)`

So,

`(1)/(x^2y^7)`