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What is the mole fraction of 25.0 g of ethanol (c2h5oh) is added to 75.0 g of water to form 96.4 mL of solution

User ANeme
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4 votes

Answer:

0.116

Step-by-step explanation:

The molar mass of ethanol is 46.07 g/mol. The moles corresponding to 25.0 g are:

25.0 g × (1 mol/46.07 g) = 0.543 mol

The molar mass of water is 18.02 g/mol. The moles corresponding to 75.0 g are:

75.0 g × (1 mol/18.02 g) = 4.16 mol

The total number of moles is:

total moles = mol ethanol + mol water = 0.543 mol + 4. 16 mol = 4.70 mol

The mole fraction of ethanol is:

X(Ethanol) = mol ethanol / total moles = 0.543 mol / 4.70 mol = 0.116

User Curpa
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