Question

A cylinder with a movable piston contains a fixed amount of gas at a constant pressure. Initially, the cylinder contains 0.25 liters of air at 0 degrees Celsius. When the temperature is increased to 35 degrees Celsius, the air will occupy what volume?

a. 0.28 L

b. 0.88 L

c. 8.75 L

d. 35.25 L

Answer 1

a. 0.28 L

Step-by-step explanation:

At constant pressure and number of moles, Using Charle's law

`\frac {V_1}{T_1}=\frac {V_2}{T_2}`

Given ,

V₁ = 0.25 L

V₂ = ?

T₁ = 0 °C

T₂ = 35 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (0 + 273.15) K = 273.15 K

T₂ = (35 + 273.15) K = 308.15 K

Using above equation as:

`(0.25)/(273.15)=(V_2)/(308.15)`

`V_2=(0.25\cdot \:308.15)/(273.15)`

New volume = 0.28 L