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Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.
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Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.

User Ganeshran
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1 Answer

2 votes

Answer:

Ic² + b²l = 13 units.

Explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

Now, Ic² + b²l

= I(- 2)² + (- 3)²l {Putting the values of b and c}

= I4 + 9l

= I13l

= 13 units.

Therefore, Ic² + b²l = 13 units. (Answer)

User Free Willaert
by
5.1k points
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