Answer:
Cost of each Computer is $225 and Cost of each Printer is $150.
Explanation:
Let the cost of the Computers be 'x'.
Let the cost of Printer be 'y'.
Given:
If he buys three computers and one printer, the cost is $825.
framing in equation form we get;
![3x+y =825 \ \ \ \ \ equation\ 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l3lmtxig00v6cyx48fcmach767xph29ts2.png)
Also Given:
if he buys 4 computers and 2 printers, the cost is $1200.
framing in equation form we get;
![4x+2y =1200 \ \ \ \ \ equation\ 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/neprjt97dkt11e5ie6hcogqostvsm5o4oe.png)
Now Multiplying equation 1 by 2 we get;
![2(3x+y)=825* 2\\\\6x+2y=1650 \ \ \ \ \ equation\ 3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/61pbn70nt1ziukmoody95bbxv1h27bzpio.png)
Now Subtracting equation 2 from equation 3 we get;
![(6x+2y)- (4x+2y) = 1650-1200\\\\6x+2y-4x-2y = 450\\\\2x=450\\\\x=(450)/(2) =\$225](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x5cofe0qjef6w1rs6b1ssglnazxciai3k4.png)
Now Substituting the value of x in equation 1 we get;
![3x+y=825\\\\3* 225+y=825\\\\675+y =825\\\\y = 825 -675\\\\y = \$150](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b3w8yqaamfouwah30rf95c9eb0q1eo7osu.png)
Hence Cost of each Computer is $225 and Cost of each Printer is $150.