Question

Ron walked 3 3/4 km on monday,4 1/3 km on Wednesday. What distance did he walk in all

Answer 1

Ron walked a total of 8 1/12 km

Explanation:

Answer 2

`8(1)/(12) \; km`

Explanation:

Distance walked by Ron on Monday =
`3(3)/(4) \; km`

Distance walked by Ron on Wednesday =
`4(1)/(3) \; km`

Now we will convert the given mixed fractions into improper fractions.

As we know that, a mixed fraction is composed of a whole number and a proper fraction.

Now,.

`3(3)/(4) =(3*4+3)/(4)=(15)/(4)`

`4(1)/(3) =(4*3+1)/(3) =(13)/(3)`

So, distance walked by Ron on Monday =
`(15)/(4)\; km`

Distance walked by Ron on Wednesday =
`(13)/(3) \; km`

Now, to find the total distance walked by Ron, we will add the distances walked by him on Monday and Wednesday.

So,

`3(3)/(4) +4(1)/(3) =(15)/(4)+ (13)/(3)`

Now, we will find the LCM of the denominators of the given fractions.

The prime factorisation of 4 and 3 is,

4 = 2 × 2

3 = 3

So, LCM (3, 4) = 2 × 2 × 3 = 12

Now, we will convert each of the given fractions into their equivalent fractions with denominator 12.

`(15)/(4)=(15*3)/(4*3)=(45)/(12)`

`(13)/(3)=(13*4)/(3*4)=(52)/(12)`

So,

`(15)/(4)+(13)/(3)=(45)/(12) +(52)/(12)=(45+52)/(12)=(97)/(12)`

Now, we will convert
`(97)/(12)` into improper fraction.

Now, 97 = 96 + 1 = 12 × 8 + 1

So, when '97' is divided by '12', then we get '8' as the quotient and '1' as the remainder.

So,

`(97)/(12) = 8(1)/(12)`

Hence, Ron walked a total distance of
`8(1)/(12)` km in both the days.