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Can someone help me I begging you all see this please

Can someone help me I begging you all see this please-example-1

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Answer:

26. Mass of sugar = 100 g

27. a).m/m % = 8.67 %

b).m/m% = 20%

28.a). Mass of sugar = 12.5 g

b).Mass of sugar = 12.5 g

c).Mass of sugar = 30 g

Step-by-step explanation:

26. Use formula:


m/m = (mass\ of\ solute)/(mass\ of\ solution) * 100

m/m = 20%

mass of solution = 500 g

mass of Solute = mass of sugar = ?

insert in the formula,


20 = (mass\ of\ solute)/(500) * 100


mass\ of\ solute = 20 * 5

mass of solute = 100 g

27. a)


m/m = (mass\ of\ solute)/(mass\ of\ solution) * 100

mass of Barium hydroxide(solute) = 13 g

mass of solution = 150 g


m/m = (13)/(150) * 100

m/m % = 8.67 %

b).


m/m = (mass\ of\ solute)/(mass\ of\ solution) * 100

mass of Glucose (solute) = 50 g

mass of solution = 250 g


m/m = (50)/(250) * 100

m/m% = 20%

28. a)


m/m = (mass\ of\ solute)/(mass\ of\ solution) * 100

m/m% = 5

mass of solution = 250 g

mass of solute = ?


mass\ of\ solute= (mass\ of\ solution)/(100) * m/m


mass\ of\ solute= (250)/(100) * 5

mass of sugar = 12.5 g

b).

m/m% = 2.5%

mass of solution = 500 g

mass of solute = ?


mass\ of\ solute= (mass\ of\ solution)/(100) * m/m


mass\ of\ solute= (500)/(100) * 2.5

mass of sugar = 12.5 g

c).

m/m% = 3 %

mass of solution = 1 kg = 1000 g

mass of solute = ?


mass\ of\ solute= (1000)/(100) * 3

Mass of sugar = 30 g

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