Question

The given line passes through the points (-4,-3) and (4,

1).
What is the equation, in point-slope form, of the line that is
perpendicular to the given line and passes through the
point (-4, 3)?
Y-3 = -2(x + 4
3
+
-5 6 -3 -2 -1.
3+
(x + 4)
= 2x + 4)

Answer 1

Explanation:

first we gotta find the slope of the first line

(-4,-3),(4,1)

slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2

so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :

1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope

y - y1 = m(x - x1)

slope = -2

(-4,3)...x1 = -4 and y1 = 3

now sub

y - 3 = -2(x - (-4) =

y - 3 = -2(x + 4) <=====