Answer:
m(CuSO4×5H2O)=424.0 g
M(CuSO4×5H2O)=249.68 g/mol
n=m/M
n(CuSO4×5H2O)=1.7 mol
There are 9 atoms of oxygen in each formula unit of CuSO4×5H2O. Therefore,
n(O)=8.5 mol
M(O)=16 g/mol
m=M×n
m(O)=135.6 g
Step-by-step explanation:
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