Question

HELP/ANSWER PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

Answer 1

1.
`y=(1)/(5)x-(32)/(5)`

2.
`y=-5x+30`

Explanation:

The line
`y=-5x+5` has the slope
`m_1=-5`

1. Perpendicular line to the given line has the slope
`m_2` for which

`m_1\cdot m_2=-1,`

so

`-5\cdot m_2=-1\\ \\m_2=(1)/(5)`

Hence, the equation of the perpendicular line passing through the point (7,-5) is

`y-(-5)=(1)/(5)(x-7)\\ \\y+5=(1)/(5)x-(7)/(5)\\ \\y=(1)/(5)x-(32)/(5)`

2. Parallel line to the given line has the slope
`m_3` for which

`m_3=m_1,`

so

`m_3=-5`

Hence, the equation of the parallel line passing through the point (7,-5) is

`y-(-5)=-5(x-7)\\ \\y+5=-5x+35\\ \\y=-5x+30`