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How many integers have a square root that is greater than 10 and less than 11?

User Callum
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2 Answers

2 votes

Answer:

20

Explanation:

We know that 10² = 100, so all integers above 100 have a square root greater than 10. Similarly, 11² = 121, so all integers below 121 have a square root less than 11. So, we want the integers from 101 through 120, inclusive. There are integers from through (just as there are 20 integers from 1 through 20).

User Yannic Hamann
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20 because 10 squared is 100 and 11 squared is 121 so any integer between those two numbers
User Denis Anisimov
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