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Select all the points that are solutions to the system of linear inequalities that is listed below 10x + 4y < 12

8x - 3y > 20
. (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

2 Answers

6 votes

Answer:

(3,-8)(2,-10)

Explanation:

User Nunespascal
by
5.0k points
7 votes

Answer:

(3,-8)

(2,-10)

Explanation:

we have


10x + 4y < 12 ----> inequality A


8x- 3y > 20 ----> inequality B

we know that

If a point is a solution of the system of inequalities, then the point must satisfy both inequalities (makes true both inequalities)

Verify all the points

Substitute the value of x and the value of y of each point in both inequalities

Case 1) point (3,-8)

For x=3, y=-8

inequality A


10(3) + 4(-8) < 12


-2 < 12 ----> is true

inequality B


8(3)- 3(-8) > 20


48 > 20 ---> is true

therefore

The point is a solution of the system of linear inequalities

Case 2) point (2,5)

For x=2, y=5

inequality A


10(2) + 4(5) < 12


40 < 12 ----> is not true

therefore

The point is not a solution of the system of linear inequalities

Case 3) point (-5,1)

For x=-5, y=1

inequality A


10(-5) + 4(1) < 12


-46 < 12 ----> is true

inequality B


8(-5)- 3(1) > 20


-43 > 20 ---> is not true

therefore

The point is not a solution of the system of linear inequalities

Case 4) point (10,3)

For x=10, y=3

inequality A


10(10) + 4(3) < 12


112 < 12 ----> is not true

therefore

The point is not a solution of the system of linear inequalities

Case 5) point (2,-10)

For x=2, y=-10

inequality A


10(2) + 4(-10) < 12


-20 < 12 ----> is true

inequality B


8(2)- 3(-10) > 20


46 > 20 ---> is true

therefore

The point is a solution of the system of linear inequalities

see the attached figure to better understand the problem

If a ordered pair is a solution of the system , then the ordered pair must lie in the shaded area of the solution set

Select all the points that are solutions to the system of linear inequalities that-example-1
User GitGitBoom
by
5.6k points