Answer:
(3,-8)
(2,-10)
Explanation:
we have
----> inequality A
----> inequality B
we know that
If a point is a solution of the system of inequalities, then the point must satisfy both inequalities (makes true both inequalities)
Verify all the points
Substitute the value of x and the value of y of each point in both inequalities
Case 1) point (3,-8)
For x=3, y=-8
inequality A
![10(3) + 4(-8) < 12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/r02zv76igxb4k9ew9bxenmn2preodavyib.png)
----> is true
inequality B
---> is true
therefore
The point is a solution of the system of linear inequalities
Case 2) point (2,5)
For x=2, y=5
inequality A
![10(2) + 4(5) < 12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5n0kebusbudo3v8o3p6w5xx5ek72bzzn34.png)
----> is not true
therefore
The point is not a solution of the system of linear inequalities
Case 3) point (-5,1)
For x=-5, y=1
inequality A
![10(-5) + 4(1) < 12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vbbgjuljfoexdqrcldszu5kh84kd8cf4a7.png)
----> is true
inequality B
---> is not true
therefore
The point is not a solution of the system of linear inequalities
Case 4) point (10,3)
For x=10, y=3
inequality A
![10(10) + 4(3) < 12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tjah9emx8aq3iv6q3muzdmx3rm888qi9sk.png)
----> is not true
therefore
The point is not a solution of the system of linear inequalities
Case 5) point (2,-10)
For x=2, y=-10
inequality A
![10(2) + 4(-10) < 12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zzi0clz4zakj389iq8xnq224mj5dof0you.png)
----> is true
inequality B
---> is true
therefore
The point is a solution of the system of linear inequalities
see the attached figure to better understand the problem
If a ordered pair is a solution of the system , then the ordered pair must lie in the shaded area of the solution set