Question

1. (NH)2CrO-

a) Number of moles of H:
b) Number of moles of N:
2. Ag.SO.
a) Molar Mass:
b) Percent Composition of Ag:
c) Percent Composition of S:
d) Percent Composition of O:​

Answer 1

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The
`(NH)_2CrO` is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:​

Answer:

a) Molar Mass: 155.93 Kg

b) Percent Composition of Ag: 69%

c) Percent Composition of S: 20.5%

d) Percent Composition of O:​ 10.2%

Step-by-step explanation:

Molar mass = molar mass of Ag + molar mass of S + molar mass of O

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

=
`\frac{ \text{mass due  to Ag}}{\text {total molar mass}}  * 100`

=
`(107.87)/(155.93) * 100`

= 0.69 \times 100

= 69%

Percent Composition of S:

=
`\frac{ \text{mass due  to S}}{\text {total molar mass}}  * 100`

=
`(32.06)/(155.93) * 100`

= 0.205 \times 100

= 20.5%

Percent Composition of O:

=
`\frac{ \text{mass due  to O}}{\text {total molar mass}}  * 100`

=
`(16.00)/(155.93) * 100`

= 0.102 \times 100

= 10.2%