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What interval contains a positive solution to the equation 0.2x^2-0.8x=1.6

1 Answer

4 votes

Explanation:

0.2x² − 0.8x = 1.6

Multiply both sides by 5.

x² − 4x = 8

Complete the square by adding 4 to both sides.

x² − 4x + 4 = 12

(x − 2)² = 12

x − 2 = ±√12

x = 2 ± √12

The positive solution is x = 2 + √12 ≈ 5.46.

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