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Consider the linear system of equations Y = 2/5x - 1 and 2x -3y + 1 = 0

User Noneme
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2 Answers

3 votes

Final answer:

The question involves solving a system of linear equations from high school algebra. Substituting Y from the first equation into the second and solving for x, we find that x = -5 and Y = -3.

Step-by-step explanation:

The student is asking about solving a system of linear equations, which is a concept in algebra that falls under high school mathematics. To find the solution to the given linear system, we can use either substitution or elimination methods. Let's use substitution since the first equation has Y isolated.

From the first equation Y = 2/5x - 1, we substitute for Y in the second equation, which gives us 2x - 3(2/5x - 1) + 1 = 0. Simplifying, we get 2x - 6/5x + 3 + 1 = 0, which further simplifies to 4/5x + 4 = 0. Solving for x gives x = -5. Substituting x back into the first equation to find Y yields Y = 2/5(-5) - 1, so Y = -3. Therefore, the solution to the system of equations is x = -5 and Y = -3, which is the point where the two lines intersect.

User Aztaroth
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4.5k points
7 votes

Answer:

The solution is the point (-5,-3)

Step-by-step explanation:

The complete question is

Consider the linear system of equations y = 2/5x - 1 and 2x -3y + 1 = 0

The solution of the system of equations is?

we have


y=(2)/(5)x-1 ----> equation A


2x-3y+1=0 ----> equation B

Solve by substitution

substitute the equation A in equation B


2x-3((2)/(5)x-1)+1=0

solve for x


2x-(6)/(5)x+3+1=0


2x-(6)/(5)x+4=0

Multiply by 5 both sides to remove the fraction


10x-6x+20=0


4x+20=0

subtract 20 both sides


4x=-20

divide by 4 both sides


x=-5

Find the value of y


y=(2)/(5)(-5)-1


y=-3

The solution is the point (-5,-3)

User Tom Metz
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5.0k points