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The proof that ΔEFG ≅ ΔJHG is shown.

Given: G is the midpoint of HF, EF ∥ HJ, and EF ≅ HJ.

Prove: ΔEFG ≅ ΔJHG

Triangles E F G and J H G share common point G.


Statement

Reason
1. G is the midpoint of HF 1. given
2. FG ≅ HG 2. def. of midpoint
3. EF ∥ HJ 3. given
4. ? 4. alt. int. angles are congruent
5. EF ≅ HJ 5. given
6. ΔEFG ≅ ΔJHG 6. SAS What is the missing statement in the proof?

∠FEG ≅ ∠HJG
∠GFE ≅ ∠GHJ
∠EGF ≅ ∠JGH
∠GEF ≅ ∠JHG

User Wlh
by
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2 Answers

17 votes
17 votes

Answer:

B.∠GFE ≅ ∠GHJ

Explanation:

got it correct on my quiz

User Deepak Bala
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3.1k points
25 votes
25 votes

Answer: ∠GFE ≅ ∠GHJ

Explanation:

In triangle EFG, we have side FG (which is opposite angle E) and EF (the side opposite angle G).

For SAS, we need the angle in between these sides, which would be angle F.

User Joshua Dyck
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2.6k points