Question

A 0.20 mol sample of MgCl(s) and a 0.10 mol sample of KCl(s) are dissolved in water and diluted to 500 mL. What is the concentration of Cl- in the solution?

Answer 1

0.6 Molar

Step-by-step explanation:

According to the Question,

In 500 mL of water ,

0.2 mol sample of MgCl is present and 0.1 mol of KCl is present.

Thus ,

Concentration of Cl anion in the solution will be the sum of Cl anion concentration from MgCl and KCl.

From MgCl , 0.2 mol of Cl anion will come and 0.1 mol of KCl anion will come ,

Thus , 0.3 mol of Cl anion will come totally .

So, Cl anion concentration will be
`(0.3)/(0.5)` = 0.6 M