Answer:
The probability that 5 chosen bagels of which exactly 3 are Asiago cheese = 0.3087 or 30.87%
Explanation:
Given:
Total bagels brought to school = 10
Number of Asiago cheese bagels = 7
To find the probability of randomly choosing 5 Asiago cheese bagels of which exactly 3 are Asiago cheese.
Solution:
Let probability of choosing an Asiago cheese bagel be the successful event.
Probability of choosing one Asiago cheese bagels =
![(7)/(10)=0.7](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1pmjm4t9510dhp4g1p21pgrcl0540tss8n.png)
Probability of success = 0.7
Probability of failure ( not choosing an Asiago cheese bagel) = 1 - Probability of success =
![1-0.7=0.3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1cuocpxm5sbn8qw2bsujydc90gwmzxolpu.png)
Using Bernoulli Trials
To calculate the binomial probability of obtaining exactly
events in
trials the formula used is:
⇒
![nCr.p^r.q^((n-r))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ixylrud88vfavrtvi9fo9yux1zynxrhhqv.png)
where
Probability of success
Probability of failure
Thus, probability of randomly choosing 5 Asiago cheese bagels of which exactly 3 are Asiago cheese can be calculated as :
⇒
![5C3(0.7)^3(0.3)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1v8d9u57jbk29x7blxlw8myb4ud6jb6g3q.png)
⇒
![(5!)/((5-3)!3!)(0.343)(0.09)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rjaegimhvcr9qoqzuxua17q20md5c9t5jg.png)
⇒
![(5!)/((2)!3!)(0.343)(0.09)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2rpr4kudcr4mpc5t6n09kbp397d24dz8mx.png)
⇒
![10(0.343)(0.09)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fchlgfimkq7ka2ety7qrt2nguiusq83k3n.png)
⇒
(Answer)