Question

Write the equation of the line that passes through the points (8, –1) and (2, –5) in standard form, given that the point-slope form is y + 1 = (x – 8).

Answer 1

The answer is 2x + -3y = 19

Explanation:

..

Answer 2

`2x-3y=19`

Explanation:

we have the ordered pairs

(8, –1) and (2, –5)

Find the slope

The formula to calculate the slope between two points is equal to

`m=(y2-y1)/(x2-x1)`

substitute the values in the formula

`m=(-5+1)/(2-8)`

`m=(-4)/(-6)`

simplify

`m=(2)/(3)`

The equation of the line in point slope form is

`y-y1=m(x-x1)`

we have

`m=(2)/(3)`

`point\ (8,-1)`

substitute

`y+1=(2)/(3)(x-8)`

Convert to standard form

The equation of the line in standard form is equal

`Ax+By=C`

where

A is a positive integer

B and C are integers

we have

`y+1=(2)/(3)(x-8)`

Multiply by 3 both sides to remove the fraction

`3y+3=2(x-8)`

apply distributive property right side

`3y+3=2x-16`

Group the variables in one side and the constants in the other side

`2x-3y=3+16`

`2x-3y=19` ---> equation in standard form