Question

Find the center and radius of the circle that has the equation ( +7)^2 +(−4)^2 = 49

Answer 1

For the given circle, the center is at (-7,4) and radius is 7

Explanation:

Given equation of the circle is
`(x+7)^2+(y-4)^2=49\hfill (1)`

To find the center and radius of given circle with the help of its equation:

Equation of the circle is of the form

(x-h)^2+(y-k)^2=r^2\hfill (2)[/tex] with center at (h,k) and radius is r.

Given
`(x+7)^2+(y-4)^2=49`

The above equation can be written as,

`(x-(-7))^2+(y-4)^2=7^2\hfill (3)`

Now comparing the equations (2) and (3) we get

h=-7, k=4 and r=7

Therefore center at (h,k) is (-7,4) and radius is 7

For the given circle, the center is at (-7,4) and radius is 7