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Consider the following intermediate reactions. CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ 2H2O(g)->2H2O(I) ΔH2=-88 kJ The overall chemical reaction is as follows. CH4(g)+2O2(g)->CO2(g)+2H2O(I) ΔH2=-890 kJ
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Consider the following intermediate reactions.

CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ
2H2O(g)->2H2O(I) ΔH2=-88 kJ
The overall chemical reaction is as follows.
CH4(g)+2O2(g)->CO2(g)+2H2O(I) ΔH2=-890 kJ
What is the correct enthalpy diagram using the Hess law for this system?

Consider the following intermediate reactions. CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ-example-1
Consider the following intermediate reactions. CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ-example-1
Consider the following intermediate reactions. CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ-example-2
Consider the following intermediate reactions. CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ-example-3
Consider the following intermediate reactions. CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ-example-4
User Vonetta
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4 votes

Answer:

The answer is A on edge

Step-by-step explanation:

User PuppyKevin
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