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What isthe turning point of the parabola equation isY=(x+2)(x-8)​

1 Answer

2 votes

Answer:

(3, - 25 )

Explanation:

Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0

The the x- coordinate of the turning point is

x = -
(b)/(2a)

Given

y = (x + 2)(x - 8) ← expand factors using FOIL

= x² - 6x - 16 ← in standard form

with a = 1 and b = - 6, thus

x = -
(-6)/(2) = 3

Substitute x = 3 into the equation for corresponding value of y

y = (3 + 2)(3 - 8) = 5(- 5) = - 25

turning point at (3, - 25 )

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