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3 votes
A chess player won 48 of the games he played. If the ratio of wins to loses was 8:7, how many games did he play total?​

2 Answers

4 votes

Final answer:

The chess player played a total of 56 games.

Step-by-step explanation:

To find the total number of games the chess player played, we need to determine the ratio of wins and losses. The ratio of wins to losses is given as 8:7. This means for every 8 wins, there are 7 losses. Since the player won a total of 48 games, we can set up the following proportion:

8/7 = 48/x

Cross-multiplying, we get 8x = 7 * 48. Solving for x, we find that the player played a total of 56 games.

User DenisFLASH
by
7.8k points
4 votes

Answer:

the answer would be 90

Step-by-step explanation:

first you multiply 8 until you get 48, which would be 6 times, then do the same thing for 7 (7x6), which would be 42 and just add it all together and you get 90

User Juve
by
8.1k points
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