Question

A room has dimensions 6.8m x 9.2m. Steven wants to paint the walls of the room. A large tin of paint covers 20m^2 and cost £11.75. Ignoring windows and doors, and allowing for 2 coats of paint, how much will it cost Steven to paint the room.

Answer 1

Total cost to paint the room = £73.51

Explanation:

Given:

Dimensions of the room = 6.8 m
`*` 9.2 m

Cost of tin of paint = £11.75

A tin of paint covers an area = 20
`m^2`

To find the cost of painting the room with two coats of paint.

Solution:

Area of the room =
`length* width=6.8\ m* 9.2\ m= 62.56\ m^2`

We will use unitary method to find the amount of paint required for the room.

If
`20\ m^2` of area is covered by 1 tin of paint.

For
`1\ m^2` of area, amount of paint required =
`(1)/(20)` of a tin

Then, for
`62.56\ m^2` amount of paint required =
`(62.56)/(20)=3.128` tins of paint.

For double coats twice paint must be required.

So, total amount of paint required for painting the room with two coats of paint =
`3.128* 2=6.256` tins of paints.

Using unitary method to find total cost.

If 1 tin of paint costs = £11.75

6.256 tins of paint will cost =
`6.256* \£11.75=\£73.508\approx\£73.51`

Total cost to paint the room = £73.51