Question

(b) The shortest distance from E to DC​

Answer 1

(a) ED = 7.78

(b) EF = 5.96

Explanation:

(b)

Let F be the midpoint of CD.

tan 50° = EF/FD

EF = FD × tan 50°

EF = 5 × tan 50°

EF = 5.96

(a)

EF² + FD² = ED²

5.96² + 5² = ED²

ED = 7.78