Question

1. A projectile is launched into the air with an initial speed of vi = 40 m/s at a launch

angle of 20° above the horizontal. The projectile lands on the ground 5.0 seconds
later.
Neglecting air resistance, calculate the projectile's range and draw projectile
path

Answer 1

range = x = 188 [m]

Step-by-step explanation:

First we must find the velocity component on the horizontal axis or x-axis

`(v_(x))_(0) = 40*cos(20) \\(v_(x))_(0) = 37.58[m/s]\\`

Then using the kinematic expression that relates velocity with time, we can find the range of the projectile or the distance x.

`x=(v_(x) )_(0)*t\\ x=37.58*5\\x=188[m]`