If f(x) = 36 - {x}^(2) and g(x) = 8 - x what is the value of (f - g)(x)

asked May 14, 2021 223k views

0 votes

If

$f(x) = 36 - {x}^(2)$
and

g(x) = 8 - x

what is the value of

(f - g)(x)

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5 votes

Answer:

$- {x}^(2) + x + 24$

Explanation:

Subtract the functions:

$f - g = (36 - {x}^(2) ) - (8 - x)$

Simplify:

$(36 - {x}^(2) ) - (8 - x) \\ 36 - {x}^(2) - 8 + x \\ - {x}^(2) + x + 24$

Kelly Adams answered May 21, 2021

5.7k points

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