Question

write the equation of a line that is perpendicular to the given line and that passes through the given point y-2=-1/4(x+3);(-3,5)

Answer 1

Correct answer: y₁ = 4x + 17

Explanation:

Given: Line l : y= - 1/4 x + 5/4 and point named A(-3, 5)

Slope (gradient) of this line is s = - 1/4

The line we are looking for l₁ is perpendicular to the given l which means

l₁ ⊥ l => s₁ = - 1/ s => s₁ = 4

The equation of line through one point is: y - ya = s₁(x - xa)

y - 5 = 4 (x + 3) => y₁ = 4x + 12 + 5 => y₁ = 4x + 17

God is with you!!!

Answer 2

The answer is y=4x+17
Hope this would help!!!