Answer:
Option E) is correct
If n is an odd number then 2(n+1) represents an even number.
Explanation:
Let X=set of all odd numbers
that is
![X={\{1,3,5,7...}\}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/blpr1op9g48cntugkqk1oql30d87p363ee.png)
Let Y=set of all even numbers
that is
![Y={\{2,4,6,8...}\}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u8e4pcjgrtji6bwcyn1tpi64fe2x21cmly.png)
Verify that 2(n+1) represents an even number where n is an odd number:
Put n=1 in 2(n+1) we get
2(1+1)=2(2)=4
Put n=3 in 2(n+1) we get
2(3+1)=2(4)=8
Put n=5 in 2(n+1) we get
2(5+1)=2(6)=12
and so on.
From above results we get 2(n+1) represents an even number and is belongs to the set Y when n is an odd number.
Therefore Option E) is correct
If n is an odd number then 2(n+1) represents an even number.