Question

What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x3−1 ?

Answer 1

y = -3x + 14

Explanation:

Answer 2

The equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x3−1 is
`y = -(1)/(3)x +3.3`

Explanation:

Given:

point (4,2)

perpendicular line y =3x -1

To find:

equation of the line =?

Solution:

We are given with perpendicular line . the slope of the perpendicular line will be negative, so let us take the reciprocal of the line and change its sign. bu doing so we will get,

slope =
`-(1)/(3)`

Now we know that the equation of the line is

y =mx+b----------------------(1)

where

m is the slope

b is the y intrcept

x,y are the points through which the line pass

so now substituting the values we get

`2 =-(1)/(3) * 4 +b`

`2 = -1.3 +b`

b = 2 +1.3

b = 3.3

substituting in (1)

`y = -(1)/(3)x +3.3`