Question

If u (x) = negative 2 x squared and v (x) = StartFraction 1 Over x EndFraction, what is the range of (u circle v) (x)?

(one-third, 0)
(3, infinity)
(negative infinity, 3)
(negative infinity, positive infinity)

Answer 1

The range of (u circle v) (x) is (negative infinity, 0).

Step-by-step explanation:

To find the range of (u circle v) (x), we need to substitute v(x) into u(x), which means replacing x in u(x) with v(x).

u(x) = -2x²

So, (u circle v) (x) = -2(v(x))² = -2(1/x)² = -2/x²

The range of (u circle v) (x) is (negative infinity, 0) because as x approaches 0 from the right, (-2/x²) approaches negative infinity, and as x approaches 0 from the left, (-2/x²) approaches positive infinity.

Answer 2

C.) (negative infinity, 3)

Step-by-step explanation:

Plz trust this is correct