Question

450 J of heat are added to a 50 g block of lead. What is the resulting

temperature change? c for lead is 0.13 J/g(degC)

Answer 1

69.2°C

Step-by-step explanation:

Recall the heat energy formula

q = cmΔT

where q = heat energy ( measured in joules ) , c = specific heat , m = mass and ΔT = change in temperature.

We are given that:

• The heat energy is 450J
• The mass is 50g
• The specific heat is 0.13 J/g(degC)

Given this we want to find the temperature change.

First we want to define our variables.

Again recall that heat energy (q) = 450J , mass(m) = 50g and specific heat (c) = 0.13 J/g(degC)

Now that we have defined our variables we plug in the values of the variables into q = cmΔT and solve for the undefined variable

q = cmΔT

q = 450 , m = 50, c = 0.13

450 = (50) x (0.13) x (ΔT)

multiply 50 and .13

450 = 6.5 x (ΔT)

divide both sides by 6.5

69.2 = ΔT

The change in temperature was 69.2°C