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Could someone help me with this exercise?

Could someone help me with this exercise?-example-1
User IntoOrbit
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1 Answer

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Answer:

  • 5%: 66 2/3 mL
  • 6.5%: 133 1/3 mL

Explanation:

Let x represent the number of milliliters of 6.5% vinegar required. Then the total amount of acetic acid in the mix is ...

6.5%·x + 5%(200 -x) = 6%·200

1.5x = 200 . . . . . . . . . . . . . multiply by 100, subtract 1000

x = 200/1.5 = 133 1/3 . . . . mL of 6.5% vinegar

200-x = 66 2/3 . . . . . . . . . mL of 5% vinegar

User Niclas Von Caprivi
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