Answer: (1) x²y (2) 7pqr (3) a (4) 6a² (5) y³z²
Explanation:
(1) x^4y³ and x²y
x^4y³ = x²y(x²y²)
x²y = x²y
Therefore the Highest Common factor
x²y which is the common factor.
(2) 14p²qr^4 = 2 x 7 x p² x q x r^4
49p²q²r = 7 x 7 x p² x q² x r
35pqr = 5 x 7 x p x q x r
Therefore HCF = 7 x p x q x r
= 7pqr
(3) -a^5 = -( a x a x a x a x a )
= -(a^5)
ab³ = a x b x b x b
Therefore HCF = a
(4) 6a² = 2 x 3 x a x a
-18a6 = -( 2 x3 x 3 x a x a x a x a x a x a)
-12a² = -( 2 x 2 x 3 x a x a )
Therefore HCF = 2 x 3 x a²
= 6a²
(5) 3y³z² = 3 x y x y x y x z x z , 3 x y³ x z²
15y^4z² = 3 x 5 x y x y x y x y x y x z x z, 3 x 5 x y^4 x z²
y^6z³ = y^6 x z³
Therfore HCF = y³ x z²
= y³z²