Question

*trigonometry and area*

Find the area of a regular hexagon with a side length of 8 cm. Round to the nearest tenth.

Answer 1

166.3 cm^2 to nearest tenth.

Step-by-step explanation:

A hexagon is made up of 6 equilateral triangles.

Area of 1 triangle = 1/2 * 8 * height.

Using trig to find the height:

tan 60 = h / 4

h = 4 tan 60 = 6.928 cm

So the area of a triangle = 1/2 * 8 * 6.928

and area of the hexagon = 6 * 1/2 * 8 * 6.928

= 166.28 cm^2.

Answer 2

The correct answer is that the area of the regular octagon is 309 cm²

Step-by-step explanation:

There are several formulas for calculating the area of a regular octagon. We will use this one for solving this question because it does not require additional information .

Area = (2 * s²)/tan 22,5°

s = 8 cm

Replacing with the real values, we have:

Area = (2 * 8²)/tan 22,5°

Area = 2 * 64/0.4142

Area = 128/0.4142

Area = 309 cm² (Rounding to the nearest tenth)

Note: Same answer to question 14318729, answered by me today.