Question

How do you know the strength of oxidizing/reducing agents in questions such as these ones? I know the answer for 37 is D but I don’t know why

Answer 1

`Pd^(2+)` is the strongest oxidizing agent .

Step-by-step explanation:

It is said in the question that given reactions are spontaneous.

As
`Np^(3+)` oxidizes Ce to
`Ce^(3+)` we can say that
`Np^(3+)` is a stronger oxidizing agent than
`Ce^(3+)`.

Similarly ,
`Cd^(2+)` is stronger than
`Np^(3+)` (from first reaction).

From second reaction we can see that
`Pd^(2+)` is stronger than
`Cd^(2+)`.

The order of oxidizing strength is
`Pd^(2+)` >
`Cd^(2+)` >
`Np^(3+)` >
`Ce^(3+)` .