Answer:
Option b) is correct.
The completed factor of given expression is
![2(x-2)(x+2)(x^2+4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l257ve5wlxmm213reomwrhsi0a3a1r938t.png)
Explanation:
Given expression is
![2x^4-32](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bpf5p54fx0mypypyrrmec7vl437m51p4s3.png)
To find the completed factor for the given expression:
:
Taking the common number "2" outside to the above expression we get
![2x^4-32=2(x^4-16)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/avjt8j2exgwyzo36vs2usmagk7nju4hb54.png)
Now rewritting the above expression as below
(since 16 can be written as the number 2 to the power of 4)
![=2((x^2)^2-(2^2)^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t4cghc0dtdgh3cgqolwp7kxwqq6qj9bd8v.png)
The above expression is of the form
![a^2-b^2=(a+b)(a-b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xrl694uxzuvngew8l8a9jhupizr3bwmalc.png)
Here
and
![b=2^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4zf9hbeah49ssmf3nm79zimd8equ5jggkh.png)
Therefore it becomes
![=2(x^2+2^2)(x^2-2^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cnkqg1743zevzlpl7eyxpx0w2ocumxw9rg.png)
The above expression is of the form
![a^2-b^2=(a+b)(a-b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xrl694uxzuvngew8l8a9jhupizr3bwmalc.png)
Here
and
![b=2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s1jh9i26y5wksgzr4cnnpni94okgr0umxk.png)
Therefore it becomes
Therefore
Option b) is correct.
The completed factor of given expression is
![2(x-2)(x+2)(x^2+4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l257ve5wlxmm213reomwrhsi0a3a1r938t.png)