Question

A copper sphere was moving at 40 m/s when it hit another object. This caused all of the KE to be converted into thermal energy for the copper sphere. If the specific heat capacity of copper is 387 J/(kg ⋅ C°), what was the increase in temperature?

0.23 C°
0.81 C°
1.3 C°
2.1 C°

Answer 1

2.1 C°

Step-by-step explanation:

I got it right on the test

Answer 2

Temperature increase = 2.1 [C]

Step-by-step explanation:

We need to identify the initial data of the problem.

v = velocity of the copper sphere = 40 [m/s]

Cp = heat capacity = 387 [J/kg*C]

The most important data given is the fact that when the shock occurs kinetic energy is transformed into thermal energy, therefore it will have to be:

`E_(k)=Q\\ E_(k)= kinetic energy [J]\\Q=thermal energy [J]\\Re-employment values and equalizing equations\\\\(1)/(2) *m*v^(2)=m*C_(p)*dT  \\The masses are canceled \\\\dT=(v^(2))/(C_(p) *2) \\dT=2.1 [C]`