149k views
0 votes
A customer at a self -storage facility was offered a choice between a storage unit shaped like a cube and another unit is 2 feet longer,5 feet shorter than the first unit. The customer thinks that f the volume of the cube is x^3 the volume of the other unit would be x^3-4x^2-11x+30. Is the customer correct ?

User Arkadii
by
7.9k points

2 Answers

3 votes

Answer:the customer is incorrect

Explanation:

In a cube, all 4 sides are equal. The volume of a cube that has x as the length of each side would be x^3

If the customer thinks that f the volume of the cube is x^3, it means that each side is x. Then the other storage unit offered to the customer is 2 feet longer,5 feet shorter than the first unit. Its dimensions would be (x+ 2) feet, (x - 5) feet and x feet

The volume of the other storage unit should be

x[(x + 2)(x - 5)] = x(x^2 - 5x + 2x + 10)

= x(x^2 - 3x + 10)

= x^3 - 3x^2 + 10x

User Josh Bedo
by
8.6k points
4 votes

Answer: No, the Volume is x^3 - 3x^2 - 10x

Explanation:

Since the volume of the cubic storage unit is x^3

Therefore,

Length = x

Width = x

Height = x

For the new storage unit

Length = x + 2

Width = x

Height = x - 5

Volume = ( x + 2)(x)(x -5)

V = x (x^2 -3x - 10)

V = x^3 - 3x^2 - 10x

Therefore, the volume of the new storage unit is x^3 - 3x^2 - 10x

User Dylan Knowles
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories