Question

a line intersects the point (0,-11) and has a slope of 0. What is slope intercept equation for this line

Answer 1

Answer: y=0x-11

Let’s start by writing the model equation for slope-intercept:

y=mx+b

M-slope
X-variable
B- y-intercept

Since we know that m is the slope, let’s substitute that into the equation

y=mx+b

y=0x+b

Now we need to solve for b. Since we are given a point, let’s substitute that point into our current equation and solve for b

y=0x+b

*substitute y and x of point*

-11=0(0)+b

*multiply 0 and 0*

-11=0+b

-11=b

Let’s add that into the equation

y=mx+b

y=0x+b

y=0x-11

Hope this helps comment below for more questions :)

Answer 2

Equations written in slope-intercept have the form: y = m x + b where m is the slope and b is the y intercept point. Horizontal lines have a slope of 0 (similar to a flat ground surface) and m would be 0 for these lines.

Also, the y intercept is the point through which the horizontal line would pass. In this case, the y intercept or b is -11.

The equation would then be

y = 0x + (-11)

OR

y = 0x -11

Often we write the equation without the "0x" term:

y= -11