The second hand of a clock is 8 cm long what is the distance of the tip of the second hand travel in 10 minutes
Answer:
The distance travelled by tip of second hand in 10 minutes is 502.4 cm
Solution:
Length of second hand = 8 cm long
In one revolution it travels a circumference of a circle of which radius is 8 cm
The circumference of circle =
![2 \pi r](https://img.qammunity.org/2021/formulas/mathematics/high-school/a0fcqe3rtm7qnla1r7tzq19js64zx5paya.png)
![c = 2 * \pi * 8 = 16\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/b3io7peft2obk9ljttdctv92z551ubdcgt.png)
We are aksed to find the distance of the tip of the second hand travel in 10 minutes
Second hand complete 1 revolution in 1 minute.
Therefore, in 10 minutes it revolves 10 revolution,
In 1 revolution tip of second covers = 16π
Hence distance travelled is given as:
![\rightarrow 16 \pi *10 = 160 \pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/u4a1oum44mj1o85fp3inzrsh7t1zsiuqqy.png)
We know that π is a constant equals to 3.14
![\rightarrow 160 \pi = 160 * 3.14 = 502.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/i46axsial8m7btvtwkre0jqct7qb931ocd.png)
Thus the distance travelled by tip of second hand in 10 minutes is 502.4 cm