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A swine producer wants to know if the average weight of his pigs is different from the breed average of 230 lb. He selects a random sample of 16 weights from pigs in his herd and calculates a sample mean of 220 lb and a sample standard deviation of 25 lb. Assume that he wants to detect departure from 230 lb in either direction and that he uses a significance level of 0.10. Calculate the value of the test statistic needed to test the null hypothesis.

User Llanilek
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1 Answer

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Answer: t= -1.60

Step-by-step explanation:

Let
\mu be the population mean weight of pigs.

As per given , we have


H_0:\mu=230


H_0:\mu\\eq230

Sample size : n= 16

Sample mean =
\overline{x}=220\ lb

Sample standard deviation :
s=25\ lb

Since the population standard deviation is not known so the test is a t-test.

Test statistic for population mean :
t=\frac{\overline{x}-\mu}{(s)/(√(n))}


t=(220-230)/((25)/(√(16))) (Substitute all the values.)


t=(-10)/((25)/(4))


t=(-40)/(25)=-1.60

Hence, the value of the test statistic needed to test the null hypothesis : t= -1.60

User Roundar
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