Question

A forward-biased silicon diode is connected to a 12.0-V battery through a resistor. If the current is 12 mA and the diode potential difference is 0.70 V, what is the resistance?

Answer 1

To solve this problem we will use the concepts related to Ohm's law for which voltage, intensity and resistance are related.

Mathematically this relationship is given as

`V = IR \rightarrow R= (V)/(I)`

Where,

V= Voltage

I = Current

R = Resistance

The value of the given voltage is 12V, while the current is 12mA, therefore the resistance would be

`R = (12)/(12*10^(-3))`

`R = 1000 \Omega`

Therefore the resistance is
`1000\Omega`