1 Answer

Kliszaq · Answer 1 · 2021-07-20T21:53:01+0000

Answer:

C. Quadruple

Step-by-step explanation:

= mass

v_(i) = initial speed =

K_(i) = initial kinetic energy

Initial kinetic energy is given as

$K_(i) = (0.5) m v_(i)^(2)\\K_(i) = (0.5) m v^(2)$

v_(f) = Final speed =
2 v

Final kinetic energy is given as

$K_(f) = (0.5) m v_(f)^(2)\\K_(f) = (0.5) m (2v)^(2)\\K_(f) = 4 (0.5) m v^(2)\\K_(f) = 4 K_(i)$

Hence the kinetic energy is quadruple

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