Answer:108.71 mL
Step-by-step explanation:
Given
Volume of sample V=150 mL
concentration of sucrose solution 35 % w/w i.e. In 100 gm of sample 35 gm is sucrose
specific gravity =1.115
Density of solution
Thus
![\rho _s=1.15* 1 gm/mL=1.115\ gm/mL](https://img.qammunity.org/2021/formulas/physics/high-school/86zdc5vklnb2vs486rt2pk6zolfy9l9aa5.png)
mass of sample
![M=1.115* 150=167.25\ gm](https://img.qammunity.org/2021/formulas/physics/high-school/8burnms2zir0940s6c43q53hx77kwy38zp.png)
mass of sucrose
![m_s=0.35* 167.25=58.53\ gm](https://img.qammunity.org/2021/formulas/physics/high-school/92ghaz7ygmtys8tf7soxro16kfgz9bmwkf.png)
mass of Water
![m_w=108.71 gm](https://img.qammunity.org/2021/formulas/physics/high-school/dxs76g43ilqcfuljo5i21syexzmpj6mi79.png)
Volume of water
![=108.71* 1=108.781 mL](https://img.qammunity.org/2021/formulas/physics/high-school/i8rb6d9v6xlxw731kdpbaeli241d51d8ai.png)